Question

Answer 1

\(d.\dfrac{4}{2x-3}>0\\ < =>2x-3>0\\ < =>2x>3\\ < =>x>\dfrac{3}{2}\\ e.\dfrac{-3}{x+1}\le0\\ < =>x+1>0\\ < =>x>-1\\ f.\dfrac{2x-1}{2x+3}\ge1\\< =>\dfrac{2x+3-4}{2x+1}\ge1\\ < =>1-\dfrac{4}{2x+1}\ge1\\ < =>\dfrac{-4}{2x+1}\ge0\\ < =>2x+1< 0\\ < =>2x< -1\\ < =>x< -\dfrac{1}{2}\)

Answer 2

d.42x−3>0

=>2x−3>0

=>2x>3

=>x>32

e.−3x+1≤0

=>x+1>0

=>x>−1

f.2x−12x+3≥1

=>2x+3−42x+1≥1

=>1−42x+1≥1

=>−42x+1≥0

=>2x+1<0

=>2x<−1

=>x<−12

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