Question

Answer 1

\(\sqrt{6-4x+x^2}=x+4\)

\(\Leftrightarrow6-4x+x^2=\left(x+4\right)^2\)

\(\Leftrightarrow6-4x+x^2=x^2+8x+16\)

\(\Leftrightarrow-4x-8x+x^2-x^2=16-6\)

\(\Leftrightarrow-12x=10\)

\(\Leftrightarrow x=\dfrac{10}{-12}=-\dfrac{5}{6}\)

Answer 2

`@` `\text {Ans}`

`\downarrow`

\(\sqrt{6-4x+x^2}=x+4\)

`<=>`\(6-4x+x^2=\left(x+4\right)^2\)

`<=>`\(6-4x+x^2=x^2+8x+16\)

`<=>`\(6-4x+x^2-x^2-8x-16=0\)

`<=>`\(-12x-10=0\)
`<=> -12x=10`

`<=> x=-10/12`