a: \(\Leftrightarrow\left\{{}\begin{matrix}2x^2+4\left|y\right|=8\\-2x^2+3\left|y\right|=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left|y\right|=1\\x^2=2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\pm\sqrt{2}\\y=\pm1\end{matrix}\right.\)
b: \(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{10}{x+1}-\dfrac{5}{y-1}=5\\\dfrac{10}{x+1}-\dfrac{1}{y-1}=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{-4}{y-1}=1\\\dfrac{5}{x+1}-\dfrac{1}{2\left(y-1\right)}=2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y-1=-4\\\dfrac{5}{x+1}=2+\dfrac{1}{2\left(y-1\right)}=2+\dfrac{1}{2\cdot\left(-4\right)}=\dfrac{15}{8}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=-3\\x+1=\dfrac{40}{15}=\dfrac{8}{3}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{5}{3}\\y=-3\end{matrix}\right.\)