Question

Answer 1

a: \(=3+2\sqrt{2}-3+2\sqrt{2}=4\sqrt{2}\)

b: \(=3\left(\sqrt{5}-1\right)-4\left(\sqrt{5}-2\right)+10\left(3-\sqrt{5}\right)\)

\(=3\sqrt{5}-3-4\sqrt{5}+8+30-10\sqrt{5}\)

\(=-11\sqrt{5}+35\)

 

Answer 2

\(a,=\dfrac{3+2\sqrt{2}-3+2\sqrt{2}}{9-8}\\ =\dfrac{4\sqrt{2}}{1}\\ =4\sqrt{2}\\ b,=\dfrac{12\left(\sqrt{5}-1\right)}{5-1}-\dfrac{4\left(\sqrt{5}-2\right)}{5-4}+\dfrac{20\left(3-\sqrt{5}\right)}{9-5}\\ =3\left(\sqrt{5}-1\right)-4\left(\sqrt{5}-2\right)+5\left(3-\sqrt{5}\right)\\ =3\sqrt{5}-3-4\sqrt{5}+8+15-5\sqrt{5}\\ =-6\sqrt{5}+20\)