Question

Answer 1

1: Thay x=25 vào A,ta được:

\(A=\dfrac{2\cdot5-1}{5+2}=\dfrac{9}{7}\)

2: \(B=\dfrac{x+16-5\sqrt{x}-10}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\dfrac{\sqrt{x}-3}{\sqrt{x}+2}\)

Answer 2

\(\dfrac{A}{B}=\dfrac{2\sqrt{x}-1}{\sqrt{x}+2}:\dfrac{\sqrt{x}-3}{\sqrt{x}+2}=\dfrac{2\sqrt{x}-1}{\sqrt{x}+3}\)

\(\Rightarrow\)\(\dfrac{2\sqrt{x}-1}{\sqrt{x}-3}< \dfrac{1}{2}\)