ĐKXĐ:\(\left\{{}\begin{matrix}x\ge0\\y\ge0\end{matrix}\right.\)
\(\left\{{}\begin{matrix}3\sqrt{x}-2\sqrt{y}=-1\\2\sqrt{x}+\sqrt{y}=4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3\sqrt{x}-2\sqrt{y}=-1\\-4\sqrt{x}-2\sqrt{y}=-8\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3\sqrt{x}-2\sqrt{y}=-1\\\left(3\sqrt{x}-2\sqrt{y}\right)-\left(-4\sqrt{x}-2\sqrt{y}\right)=\left(-1\right)-\left(-8\right)\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3\sqrt{x}-2\sqrt{y}=-1\\3\sqrt{x}-2\sqrt{y}+4\sqrt{x}+2\sqrt{y}=7\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3\sqrt{x}-2\sqrt{y}=-1\\7\sqrt{x}=7\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3.1-2\sqrt{y}=-1\\\sqrt{x}=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3-2\sqrt{y}=-1\\x=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2\sqrt{y}=4\\x=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\sqrt{y}=2\\x=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=4\left(tm\right)\\x=1\left(tm\right)\end{matrix}\right.\)