Question

;-;

Answer 1

g: \(=6\sqrt{3}+\dfrac{1}{2}\cdot6\sqrt{3}-\dfrac{1}{3}\sqrt{3}\)

\(=\dfrac{26}{3}\sqrt{3}\)

h:\(=\sqrt{7}-1+\sqrt{7}+2=2\sqrt{7}+1\)

Answer 2

g) \(2\sqrt{27}+\dfrac{1}{2}\sqrt{108}-\dfrac{1}{\sqrt{3}}=6\sqrt{3}+\dfrac{1}{2}\cdot6\sqrt{3}-\dfrac{1}{\sqrt{3}}\)

    \(=9\sqrt{3}+\dfrac{1}{\sqrt{3}}=\dfrac{28\sqrt{3}}{3}\)