\(a,ĐK:x>0\\ b,P=\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}{x-\sqrt{x}+1}-\dfrac{\sqrt{x}\left(2\sqrt{x}+1\right)}{\sqrt{x}}+1\\ P=\sqrt{x}\left(\sqrt{x}+1\right)-2\sqrt{x}-1\\ P=x+\sqrt{x}-2\sqrt{x}-1=x-\sqrt{x}-1\\ c,P=x-\sqrt{x}-1=\left(x-\sqrt{x}+\dfrac{1}{4}\right)-\dfrac{5}{4}=\left(\sqrt{x}-\dfrac{1}{2}\right)^2-\dfrac{5}{4}\ge-\dfrac{5}{4}\\ P_{min}=-\dfrac{5}{4}\Leftrightarrow\sqrt{x}=\dfrac{1}{2}\Leftrightarrow x=\dfrac{1}{4}\)
a: ĐKXĐ: \(x>0\)
b: Ta có: \(P=\dfrac{x^2+\sqrt{x}}{x-\sqrt{x}+1}-\dfrac{2x+\sqrt{x}}{\sqrt{x}}+1\)
\(=x+\sqrt{x}-2\sqrt{x}-1+1\)
\(=x-\sqrt{x}\)
Tim Gia Tri Nho Nhat Cua
a) A = x - 4 can x + 9
b) B = x - 3 can x - 10
c ) C = x - can x + 1
d ) D = x + can x + 2
