Question

Answer 1

\(\dfrac{3}{2}\sqrt{6}+2\sqrt{\dfrac{2}{3}}-4\sqrt{\dfrac{3}{2}}=\dfrac{\sqrt{6}}{6}\)

\(\Leftrightarrow\dfrac{3\sqrt{6}}{2}+\dfrac{2\sqrt{6}}{3}-2\sqrt{6}-\dfrac{\sqrt{6}}{6}=0\)

\(\Leftrightarrow\dfrac{9\sqrt{6}+4\sqrt{6}-12\sqrt{6}-\sqrt{6}}{6}=0\Leftrightarrow\dfrac{0}{6}=0\Leftrightarrow0=0\)(đúng)

Answer 2

Ta có: \(\dfrac{3}{2}\sqrt{6}+2\sqrt{\dfrac{2}{3}}-4\sqrt{\dfrac{3}{2}}\)

\(=\dfrac{3}{2}\sqrt{6}+\dfrac{2}{3}\sqrt{6}-2\sqrt{6}\)

\(=\dfrac{\sqrt{6}}{6}\)