1: Thay x=16 vào A, ta được:
\(A=\dfrac{4+10}{4}=\dfrac{14}{4}=\dfrac{7}{2}\)
2: Ta có: \(B=\dfrac{1}{\sqrt{x}+2}-\dfrac{\sqrt{x}}{\sqrt{x}-2}+\dfrac{2x-\sqrt{x}+2}{x-4}\)
\(=\dfrac{\sqrt{x}-2-x-2\sqrt{x}+2x-\sqrt{x}+2}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}\)
\(=\dfrac{x-2\sqrt{x}}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}\)
\(=\dfrac{\sqrt{x}}{\sqrt{x}+2}\)