a: Ta có: \(C=\left(x^2-1\right)\cdot\left(\dfrac{1}{x-1}-\dfrac{1}{x+1}+1\right)\)
\(=\left(x-1\right)\left(x+1\right)\cdot\dfrac{x+1-x+1+x^2-1}{\left(x-1\right)\left(x+1\right)}\)
\(=x^2+1\)
b: Ta có: \(x^2\ge0\forall x\)
\(\Leftrightarrow x^2+1>0\forall x\)
hay C>0\(\forall x\) thỏa mãn ĐKXĐ