2) =\(\sqrt{14.6+14\sqrt{35}}\)-\(\sqrt{10.6+10.\sqrt{35}}\)
=\(\sqrt{64+14\sqrt{35}}\)-\(\sqrt{60+10\sqrt{35}}\)
=\(\sqrt{49+14\sqrt{35}+35}-\sqrt{25+10\sqrt{35}+35}\)
=\(\sqrt{\left(7+\sqrt{35}\right)^2}-\sqrt{\left(5+\sqrt{35}\right)^2}\)
=\(7+\sqrt{35}-5-\sqrt{35}\)
=2
5) Ta có: \(\left(2-\sqrt{3}\right)\left(\sqrt{6}+\sqrt{2}\right)\sqrt{2+\sqrt{3}}\)
\(=\dfrac{\left(4-2\sqrt{3}\right)}{2}\cdot\left(\sqrt{3}+1\right)^2\)
\(=\left(\sqrt{3}+1\right)^2\cdot\dfrac{\left(\sqrt{3}-1\right)^2}{2}\)
=2
3) =(5+4\(\sqrt{2}\))(\(9-4\left(1+\sqrt{2}\right)\))
=\(\left(5+4\sqrt{2}\right)\left(5-4\sqrt{2}\right)\)
=25-16.2
=-7
4) =\(\sqrt{\sqrt{2}-1}.\sqrt{4-3+\sqrt{2}}\)
=\(\sqrt{\sqrt{2}-1}.\sqrt{1+\sqrt{2}}\)
=\(\sqrt{2-1}\)
=1
