Question

Tìm x,y : \(\left\{{}\begin{matrix}\sqrt{x}-2=2\\\sqrt{y}-1=2\end{matrix}\right.\)

Answer 1

ĐK: \(x,y\ge0\)

\(\left\{{}\begin{matrix}\sqrt{x}-2=2\\\sqrt{y}-1=2\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}\sqrt{x}=4\\\sqrt{y}=3\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=16\left(tm\right)\\y=9\left(tm\right)\end{matrix}\right.\)

#$\mathtt{Toru}$