`a)(3x+1)(2x-3)-(x+1)(6x-1)=0`
`<=>6x^2-9x+2x-3-6x^2+x-6x+1=0`
`<=>-12x=2`
`<=>x=-1/6`
Vậy `S={-1/6}`
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`b)(2x-1)(3x-4)-(x+1)(x-2)+(x-1)(2x-1)-7x(x-2)=0`
`<=>6x^2-8x-3x+4-x^2+2x-x+2+2x^2-x-2x+1-7x^2+14x=0`
`<=>x=-7`
Vậy `S={-7}`
a: \(\Leftrightarrow6x^2-9x+3x-3-6x^2+x-6x+1=0\)
=>-11x-2=0
=>x=-2/11
b: \(\Leftrightarrow6x^2-11x+4-x^2+x+2+2x^2-3x+1-7x^2+14x=0\)
=>x+7=0
=>x=-7
`a.`\(\left(3x+1\right)\left(2x-3\right)-\left(x+1\right)\left(6x-1\right)=0\)
`=>`\(6x^2-9x+2x-3-6x^2+x-6x+1=0\)
`=>`\(-12x-2=0\)
`=>-12x=2`
`=>x=-1/6`
`b.`\(\left(2x-1\right)\left(3x-4\right)-\left(x+1\right)\left(x-2\right)+\left(x-1\right)\left(2x-1\right)-7x\left(x-2\right)=0\)
\(\Rightarrow6x^2-8x-3x+4-x^2+2x-x+2+2x^2-x-2x+1-7x^2+14x=0\)
\(\Rightarrow x+7=0\)
`=>x=-7`
\(a,6x^2+2x-9x-3-\left(6x^2+6x-x-1\right)=0\\ 6x^2-7x-3-6x^2-5x+1=0\\ -12x-2=0\\ -12x=2\\ x=-\dfrac{1}{6}\\ ---------\\ b,6x^2-3x-8x+4-\left(x^2+x-2x-2\right)+\left(2x^2-2x-x+1\right)-7x^2+14x=0\\ 6x^2-11x+4-x^2+x+2+2x^2-3x+1-7x^2+14x=0\\ x+7=0\\ x=-7\)
a) (3x + 1)(2x - 3) - (x + 1)(6x - 1) = 0
6x² - 9x + 2x - 3 - 6x² + x - 6x + 1 = 0
-12x - 2 = 0
-12x = 2
x = -1/6
b) (2x - 1)(3x - 4) - (x + 1)(x - 2) + (x - 1)(2x - 1) - 7x(x - 2) = 0
6x² - 8x - 3x + 4 - x² + 2x - x + 2 + 2x² - x - 2x + 1 - 7x² + 14x = 0
x + 7 = 0
x = -7
Vậy x = -7
