đk x >= 0
\(\dfrac{\sqrt{x}+6}{\sqrt{x}+1}-\dfrac{7}{2}>0\Leftrightarrow\dfrac{2\sqrt{x}+12-7\sqrt{x}-7}{2\left(\sqrt{x}+1\right)}>0\)
\(\Leftrightarrow\dfrac{-5\sqrt{x}+5}{2\left(\sqrt{x}+1\right)}>0\)do \(2\left(\sqrt{x}+1\right)>0\)
\(\Rightarrow-5\left(\sqrt{x}-1\right)>0\Leftrightarrow\sqrt{x}-1< 0\Leftrightarrow x< 1\)
Kết hợp đk vậy 0 =< x < 1