Question

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Answer 1

Ta có : \(S_{xq}=V=2\pi rh=\pi r^2h\)

\(\Rightarrow r\left(r-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}r=0\left(L\right)\\r=2\left(TM\right)\end{matrix}\right.\)

\(\Rightarrow V=\pi r^2h=8\pi\left(cm^3\right)\)

Answer 2

\(S_{xq}=2\pi Rh=4\pi R\), \(V=\pi R^2h=2\pi R^2\),\(S_{xq}=V\Rightarrow4\pi R=2\pi R^2\Rightarrow R=2\)(cm)

\(\Rightarrow V=8\pi\left(cm^3\right)\)