\(A=\dfrac{sin30^0+2\cdot cos45^0-3\cdot tan^{2024}45^0}{cos60^0}\)
\(=\dfrac{\dfrac{1}{2}+2\cdot\dfrac{\sqrt{2}}{2}-3\cdot1}{\dfrac{1}{2}}=\dfrac{\dfrac{1}{2}+\sqrt{2}-3}{\dfrac{1}{2}}\)
\(=2\left(\dfrac{1}{2}+\sqrt{2}-3\right)=1+2\sqrt{2}-6=2\sqrt{2}-5\)