a: \(cos24=sin\left(90-24\right)=sin66;cos87=sin\left(90-87\right)=sin3\)
Ta có: \(3^0< 40^0< 42^0< 66^0< 78^0\)
=>\(sin3^0< sin40^0< sin42^0< sin66^0< sin78^0\)
=>\(cos87^0< sin40^0< sin42^0< cos24^0< sin78^0\)
b: \(D=sin^215^0+sin^275^0-2\cdot\dfrac{cos49}{sin41}+tan26\cdot tan64\)
\(=\left(sin^215^0+cos^215^0\right)-2\cdot\dfrac{sin41}{cos41}+tan26\cdot cot26\)
=1-2+1=0