ĐKXĐ: \(x\ne0;y\ne0\)
\(\left\{{}\begin{matrix}\dfrac{6}{x}+\dfrac{5}{y}=1\\\dfrac{7}{x}-\dfrac{5}{y}=2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{13}{x}=3\\\dfrac{5}{y}=2-\dfrac{7}{x}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{13}{3}\\\dfrac{5}{y}=\dfrac{5}{13}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{13}{3}\\y=13\end{matrix}\right.\)
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