\(Q=\sqrt{12x}-2+\dfrac{14-6x}{\sqrt{3x}+1}\)
\(=2\sqrt{3x}-2+\dfrac{14-6x}{\sqrt{3x}+1}\)
\(=2\left(\sqrt{3x}-1\right)+\dfrac{14-6x}{\sqrt{3x}+1}\)
\(=\dfrac{2\left(\sqrt{3x}-1\right)\left(\sqrt{3x}+1\right)+14-6x}{\sqrt{3x}+1}\)
\(=\dfrac{2\left(3x-1\right)+14-6x}{\sqrt{3x}+1}=\dfrac{12}{\sqrt{3x}+1}\)
\(=\dfrac{12\left(\sqrt{3x}-1\right)}{3x-1}\)
mà \(Q=\dfrac{a\left(\sqrt{3x}-1\right)}{3x-1}\)
nên a=12
Đúng 1
Bình luận (0)
