Question

Answer 1

2:

a: \(\sqrt{121}+\sqrt{16}=11+4=15\)

b: \(\sqrt{144}-2\cdot\sqrt{36}=12-2\cdot6=0\)

c: \(\dfrac{1}{3}\cdot\sqrt{81}+\sqrt{225}-5\cdot\sqrt{100}\)

\(=\dfrac{1}{3}\cdot9+15-5\cdot10=3+15-50=18-50=-32\)

3:

a: \(=14\cdot8=112\)

b: \(=\sqrt{5\cdot45}=\sqrt{225}=15\)

c: \(=\sqrt{\dfrac{400}{144}}=\sqrt{\dfrac{100}{36}}=\sqrt{\dfrac{25}{9}}=\dfrac{5}{3}\)

d: \(=\sqrt{\dfrac{108}{3}}=\sqrt{36}=6\)