Ta có : \(1^2=1;\sqrt{2^2}=2\)
\(\Rightarrow\sqrt{2}>1\)
Ta có : \(2^2=4;\sqrt{2^2}+1^2=2+1=3\\ \Rightarrow2>\sqrt{2}+1\)
Ta có : \(2^2=4;\sqrt{3^2}=3\)
\(\Rightarrow2>\sqrt{3}\)
Ta có : \(7^2=49;\left(5\sqrt{2}\right)^2=25\cdot2=50\)
\(\Rightarrow7< 5\sqrt{2}\)
Ta có : \(7^2=49;\sqrt{47^2}=47\)
\(\Rightarrow7>\sqrt{47}\)
Ta có : \(1^2=1;\sqrt{3}-1=3-1=2\)
\(\Rightarrow1< \sqrt{3}-1\)
Ta có : \(2\sqrt{31}=4\cdot31=124;10^2=100\)
\(\Rightarrow2\sqrt{31}>10\)
Ta có : \(-5^2=25;-\sqrt{29}=-29\)
\(\Rightarrow-5< -\sqrt{29}\)
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