b: \(=\dfrac{2}{3+\sqrt{5}}+\dfrac{1}{3-\sqrt{5}}\)
\(=\dfrac{6-2\sqrt{5}+3+\sqrt{5}}{4}=\dfrac{9-\sqrt{5}}{4}\)
d: \(=\dfrac{\left(\sqrt{5}-1\right)^2-6\left(\sqrt{5}+1\right)}{4}\)
\(=\dfrac{6-2\sqrt{5}-6\sqrt{5}-6}{4}=-\dfrac{8\sqrt{5}}{4}=-2\sqrt{5}\)
f: \(=\dfrac{\sqrt{6}\left(\sqrt{3}-\sqrt{2}\right)}{\sqrt{3}-\sqrt{2}}-\dfrac{5\left(\sqrt{6}+1\right)}{5}\)
\(=\sqrt{6}-\sqrt{6}-1=-1\)
h: \(=\dfrac{\sqrt{6}\left(\sqrt{3}+\sqrt{2}\right)}{\sqrt{3}+\sqrt{2}}+\dfrac{5\left(\sqrt{6}+1\right)}{5}\)
=căn 6+căn 6+1
=2căn 6+1
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