\(b,\dfrac{2}{\sqrt{3}-1}\)
\(=\dfrac{3-1}{\sqrt{3}-1}\)
\(=\dfrac{\left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)}{\sqrt{3}-1}\)
\(=\sqrt{3}+1\)
\(d,\dfrac{12}{1-\sqrt{5}}\)
\(=\dfrac{3\left(5-1\right)}{-\left(\sqrt{5}-1\right)}\)
\(=-\dfrac{3\left(\sqrt{5}-1\right)\left(\sqrt{5}+1\right)}{\sqrt{5}-1}\)
\(=-3\left(\sqrt{5}+1\right)\)
\(=-3\sqrt{5}-3\)
\(f,\dfrac{\sqrt{2}}{\sqrt{8}-1}\)
\(=\dfrac{\sqrt{2}\left(\sqrt{8}+1\right)}{\left(\sqrt{8}-1\right)\left(\sqrt{8}+1\right)}\)
\(=\dfrac{\sqrt{16}+\sqrt{2}}{8-1}\)
\(=\dfrac{4+\sqrt{2}}{7}\)
\(h,\dfrac{2}{\sqrt{6}+\sqrt{5}}\)
\(=\dfrac{2\left(\sqrt{6}-\sqrt{5}\right)}{\left(\sqrt{6}+\sqrt{5}\right)\left(\sqrt{6}-\sqrt{5}\right)}\)
\(=\dfrac{2\sqrt{6}-2\sqrt{5}}{6-5}\)
\(=2\sqrt{6}-2\sqrt{5}\)
#Urushi☕
