a: Sửa đề: \(2\sqrt{\dfrac{x-1}{4}}-3=2\sqrt{\dfrac{4x-4}{9}}-\dfrac{1}{3}\)
=>\(\sqrt{x-1}\cdot\dfrac{2}{2}-3=2\cdot\dfrac{2}{3}\sqrt{x-1}-\dfrac{1}{3}\)
=>\(\sqrt{x-1}\left(\dfrac{2}{2}-\dfrac{4}{3}\right)=-\dfrac{1}{3}+3=\dfrac{8}{3}\)
=>\(\sqrt{x-1}\cdot\dfrac{-1}{3}=\dfrac{8}{3}\)
=>\(\sqrt{x-1}=-8\left(loại\right)\)
b: \(\Leftrightarrow2\sqrt{x-5}+3\cdot\dfrac{\sqrt{x-5}}{3}-\dfrac{1}{3}\cdot3\sqrt{x-5}=4\)
=>\(2\sqrt{x-5}=4\)
=>\(\sqrt{x-5}=2\)
=>x-5=4
=>x=9
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