Question

Answer 1

\(\dfrac{x+a\sqrt{x}}{a\sqrt{x}}\left(dk:x>0,a\ne0\right)\\ =\dfrac{\sqrt{x^2}+a\sqrt{x}}{a\sqrt{x}}=\dfrac{\sqrt{x}\left(\sqrt{x}+a\right)}{a\sqrt{x}}=\dfrac{\sqrt{x}+a}{a}\)

Answer 2

`(x+a\sqrt{x})/(a\sqrt{x})` 

Điều Kiện : `x>0;a\ne0`

`=(\sqrt{x}(\sqrt{x}+a))/(a\sqrt{x})`

`=(\sqrt{x}+a)/(a)`

Answer 3

5) ĐK: x>0; a khác 0

 \(\dfrac{x+a\sqrt{x}}{a\sqrt{x}}=\dfrac{\sqrt{x}\left(a+\sqrt{x}\right)}{a\sqrt{x}}=\dfrac{a+\sqrt{x}}{a}\)