Question

Answer 1

Đk: `x in RR`.

`<=> |2x-1|=3`

`<=> 2x-1=3` hoặc `2x - 1 = -3`

`<=> x= 2` hoặc `x = -1`

Answer 2

\(\sqrt{\left(2x+1\right)^2}\)=3( ĐKXĐ: 2x+1\(\ge\)0<=>x\(\ge\)-\(\dfrac{1}{2}\)

/2x+1/=3

TH1: 2x+1=3

<=>2x= 4

<=> x=2(TM)

TH2: 2x+1=-3

<=> 2x= -2

<=> x=-1(TM)