Question

Answer 1

1: \(=\left(2\sqrt{6}-4\sqrt{3}+\dfrac{9}{2}\sqrt{2}\right)\cdot3\sqrt{6}\)

\(=2\sqrt{6}\cdot3\sqrt{6}-4\sqrt{3}\cdot3\sqrt{6}+\dfrac{9}{\sqrt{2}}\cdot3\sqrt{6}\)

\(=36-12\sqrt{18}+27\sqrt{3}\)

\(=36-36\sqrt{2}+27\sqrt{3}\)

2: \(=\left(2-\sqrt{6}+\dfrac{5}{3}\sqrt{6}\right)\cdot\sqrt{6}\)

=(2+2/3*căn 6)*căn 6

=2*căn 6+2/3*6

=2*căn 6+4

4: \(=\dfrac{\sqrt{15}\left(20\sqrt{20}-15\sqrt{45}+5\sqrt{5}\right)}{\sqrt{15}}\)

\(=40\sqrt{5}-45\sqrt{5}+5\sqrt{5}=0\)

6: \(=\dfrac{\sqrt{5}\left(\sqrt{2}-\sqrt{3}\right)}{2\left(\sqrt{2}-\sqrt{3}\right)}=\dfrac{\sqrt{5}}{2}\)