Bài 1:
a: Khi x=16 thì \(A=\dfrac{4+1}{4-1}=\dfrac{5}{3}\)
b: \(P=\dfrac{\sqrt{x}+1}{\sqrt{x}-1}\cdot\dfrac{x+2\sqrt{x}+1-3\sqrt{x}-1}{x-1}\)
\(=\dfrac{1}{\left(\sqrt{x}-1\right)^2}\cdot\dfrac{x-\sqrt{x}}{1}=\dfrac{\sqrt{x}}{\sqrt{x}-1}\)
c: Để |P-2|=2-P thì P-2<=0
=>\(\dfrac{\sqrt{x}-2\sqrt{x}+2}{\sqrt{x}-1}< =0\)
=>\(\dfrac{\sqrt{x}-2}{\sqrt{x}-1}>=0\)
=>x>=4 hoặc 0<x<1