\(A=\dfrac{x}{\sqrt{x}-1}-\dfrac{\sqrt{x}+1}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)
\(=\dfrac{x}{\sqrt{x}-1}-\dfrac{1}{\sqrt{x}-1}=\dfrac{x-1}{\sqrt{x}-1}\)
\(=\dfrac{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}{\sqrt{x}-1}=\sqrt{x}+1\)
b.
Tại \(x=4\Rightarrow A=\sqrt{4}+1=2+1=3\)