Question

Answer 1

a: \(AH=\sqrt{9^2-5.4^2}=7.2\left(cm\right)\)

AC=9^2/7,2=11,25(cm)

=>BC=6,75(cm)

sin A=cos C=BC/AC=3/5

cos A=sin C=4/5

tan A=cot C=3/4

cot A=tan C=4/3

b: \(BH=\sqrt{13^2-12^2}=5\left(cm\right)\)

CA=13^2/12=169/12(cm)

\(BA=\sqrt{\left(\dfrac{169}{12}\right)^2-13^2}=\dfrac{65}{12}\left(cm\right)\)

\(sinA=cosC=\dfrac{BC}{AC}=13:\dfrac{169}{12}=\dfrac{12}{13}\)

cos A=sin C=5/13

tan A=cot C=12/5

cot A=tan C=5/12