a:
2: \(HB\cdot HC=AH^2\)
\(AE\cdot AB=AH^2\)
Do đó: \(HB\cdot HC=AE\cdot AB\)
b: \(\dfrac{EB}{FC}=\dfrac{BH^2}{AB}:\dfrac{CH^2}{AC}=\dfrac{BH^2}{AB}\cdot\dfrac{AC}{CH^2}=\left(\dfrac{AB}{AC}\right)^4\cdot\dfrac{AC}{AB}\)
\(=\left(\dfrac{AB}{AC}\right)^3=tan^3C\)