Question

Answer 1

a: Khi x=9/16 thì \(B=\left(\dfrac{3}{4}-3\right):2=\dfrac{-9}{4}:2=-\dfrac{9}{8}\)

b: \(M=A\cdot B\)

\(=\dfrac{\sqrt{x}+3+\sqrt{x}+11}{x-9}\cdot\dfrac{\sqrt{x}-3}{2}\)

\(=\dfrac{2\sqrt{x}+14}{\sqrt{x}+3}\cdot\dfrac{1}{2}=\dfrac{\sqrt{x}+7}{\sqrt{x}+3}\)

Answer 2

a,B=\(\left(\dfrac{3}{4}-3\right):2=\dfrac{-9}{4}:2=-\dfrac{9}{8}\)

b,\(M=A.B\)

=\(\dfrac{\sqrt{x}+3+\sqrt{x}+11}{x-9}.\dfrac{\sqrt{x}-3}{2}\)=\(\dfrac{2\sqrt{x}+14}{\sqrt{x}+3}.\dfrac{1}{2}=\dfrac{\sqrt{x}+7}{\sqrt{x}+3}\)