Question

Answer 1

hpt vô no khi

\(\dfrac{3}{-m}=\dfrac{-2}{2}\ne\dfrac{1}{3}\\ \dfrac{-3}{m}=-\dfrac{2}{2}\\ -6=-2m\\ m=\left(-6\right):\left(-2\right)\\ m=3\)

Answer 2

\(\left\{{}\begin{matrix}3x-2y=1\\-mx+2y=3\end{matrix}\right.\) .Pt VN <=> \(\dfrac{3}{-m}\)\(\ne\) \(\dfrac{-2}{2}\) <=> m\(\ne\) 3