a: \(Q=\dfrac{3x+3\sqrt{x}-3-x+1-x-4\sqrt{x}-4}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}\)
\(=\dfrac{x-\sqrt{x}-6}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}=\dfrac{\sqrt{x}-3}{\sqrt{x}-1}\)
b: Khi \(x=4+2\sqrt{3}\) thì \(Q=\dfrac{\sqrt{3}+1-3}{\sqrt{3}+1-1}=\dfrac{\sqrt{3}-2}{\sqrt{3}}=\dfrac{3-2\sqrt{3}}{3}\)
c: Để Q=3 thì \(3\sqrt{x}-3=\sqrt{x}-3\)
=>x=0