Question

Answer 1

a: \(\Leftrightarrow2x+3=3+2\sqrt{2}\)

=>2x=2 căn 2

hay x=căn 2

b: \(\Leftrightarrow\sqrt{3x}+10=10+4\sqrt{6}\)

=>căn 3x=căn 96

=>3x=96

hay x=32

c: =>3x-2=7-4 căn 3

=>3x=9-4căn 3

hay \(x=\dfrac{9-4\sqrt{3}}{3}\)

Answer 2

a)2x+3=3+2\(\sqrt{2}\)

2x=2\(\sqrt{2}\)

=>x=\(\sqrt{2}\)

b)10+\(\sqrt{3x}\)=10+\(2\sqrt{6}\)

\(\sqrt{3x}=4\sqrt{6}\)

3x=96

x=32

c) 3x-2=7-2\(\sqrt{3}\)

3x=9-2\(\sqrt{3}\)

x=\(\dfrac{9-2\sqrt{3}}{3}\)