Câu 1:
a: \(A=\dfrac{1-a^2}{1-\sqrt{a}}=\dfrac{\left(1-a\right)\left(1+a\right)}{1-\sqrt{a}}=\left(1+a\right)\left(1+\sqrt{a}\right)\)
b: \(B=\dfrac{\left(\sqrt{x-1}-\sqrt{2}\right)\left(\sqrt{x-1}+\sqrt{2}\right)}{\sqrt{x-1}-\sqrt{2}}=\sqrt{x-1}+\sqrt{2}\)