1: \(A=3\sqrt{3}-4\sqrt{3}+\dfrac{1}{2}\cdot4\sqrt{3}=-\sqrt{3}+2\sqrt{3}=\sqrt{3}\)
2:
a: \(C=\dfrac{x+9-x+3\sqrt{x}}{x-9}\cdot\dfrac{\sqrt{x}\left(\sqrt{x}-3\right)}{2\sqrt{x}+2}=\dfrac{3\sqrt{x}}{2\sqrt{x}+2}\)
b: Để C<1 thì \(\sqrt{x}-2< 0\)
hay x<4

