\(a,\Leftrightarrow\left\{{}\begin{matrix}x=5-y\\\dfrac{10}{3}-\dfrac{2}{3}y-\dfrac{3}{2}y=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=5-y\\\dfrac{13}{6}y=\dfrac{13}{3}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=5-y=3\\y=2\end{matrix}\right.\)
\(b,\Leftrightarrow\left\{{}\begin{matrix}-\dfrac{1}{2}x+\dfrac{1}{3}+\dfrac{1}{3}x=0\\y=x+1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{6}x=\dfrac{1}{3}\\y=x+1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=3\end{matrix}\right.\)
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