a: Đặt căn (x-2)=a
|y-1|=b
\(\Leftrightarrow\left\{{}\begin{matrix}a+b=2\\a+3b=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}b=2\\a=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x-2=0\\y-1\in\left\{2;-2\right\}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y\in\left\{3;-1\right\}\end{matrix}\right.\)