Điều kiện: \(x\) ≥ 0
\(A=\dfrac{x-\sqrt{x}+1}{\sqrt{x}}\)
\(=\dfrac{\left[\left(\sqrt{x}\right)^2-2.\sqrt{x}.\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2\right]+\dfrac{3}{4}}{\sqrt{x}}\)
\(=\dfrac{\left(\sqrt{x}-\dfrac{1}{2}\right)^2+\dfrac{3}{4}}{\sqrt{x}}\)