\(a,A=\dfrac{x}{\sqrt{x}-1}-\dfrac{\sqrt{x}\left(2\sqrt{x}-1\right)}{\sqrt{x}\left(\sqrt{x}-1\right)}=\dfrac{x-2\sqrt{x}+1}{\sqrt{x}-1}\\ A=\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}-1}=\sqrt{x}-1\\ b,x=3+2\sqrt{2}=\left(\sqrt{2}+1\right)^2\Leftrightarrow\sqrt{x}=\sqrt{2}+1\\ \Leftrightarrow A=\sqrt{2}+1-1=\sqrt{2}\)