Từ câu tìm x để biểu thức T=√4x-3 xác định làm như nào ạ?
\(A=8-7=1\\ B=8+5+3=16\\ P=7-6+4=5\\ Q=16\cdot3-9\cdot4=48-36=12\\ T=\sqrt{4x-3}\left(ĐK:4x-3\ge0\Leftrightarrow x\ge\dfrac{3}{4}\right)\\ A=\sqrt{2x-3}\left(ĐK:2x-3\ge0\Leftrightarrow x\ge\dfrac{3}{2}\right)\\ C=\dfrac{5+5\sqrt{2}-5+5\sqrt{2}}{\left(1-\sqrt{2}\right)\left(1+\sqrt{2}\right)}=\dfrac{10\sqrt{2}}{-1}=-10\sqrt{2}\\ B=\dfrac{x+4\sqrt{x}+4+2x-4\sqrt{x}}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}=\dfrac{3x+4}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\\ P=\dfrac{2x+3\sqrt{x}+9+3\sqrt{x}-9}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=\dfrac{2\sqrt{x}\left(\sqrt{x}+3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=\dfrac{2\sqrt{x}}{x-9}\)
