1: \(B=\dfrac{x+6\sqrt{x}+9-x+6\sqrt{x}-9-36}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\)
\(=\dfrac{12}{\sqrt{x}+3}\)
Để A=B thì \(7x+21\sqrt{x}-2\sqrt{x}-6=24\sqrt{x}+12\)
\(\Leftrightarrow7x-5\sqrt{x}-18=0\)
\(\Leftrightarrow\sqrt{x}-2=0\)
hay x=2