Question

Answer 1

\(a,=\sqrt{2}+2\sqrt{2}+5\sqrt{2}=8\sqrt{2}\\ b,=4\sqrt{3}+3\sqrt{3}-3\sqrt{5}+\sqrt{5}=7\sqrt{3}-2\sqrt{5}\\ c,=6+\sqrt{15}-2\sqrt{15}=6-\sqrt{15}\\ d,=\left(\sqrt{7}-2\sqrt{3}\right)\sqrt{7}-4\sqrt{21}=7-2\sqrt{21}-4\sqrt{21}=7-6\sqrt{21}\\ e,=\dfrac{3\sqrt{5}-3+3\sqrt{5}+3}{4}=\dfrac{6\sqrt{5}}{4}=\dfrac{3\sqrt{5}}{2}\\ f,=12-2\sqrt{35}+2\sqrt{35}=12\\ g,=3-\sqrt{5}+\sqrt{5}+3=6\\ h,=2-\sqrt{3}-2-\sqrt{3}=-2\sqrt{3}\\ i,=2\sqrt{a}+7\sqrt{a}-5\sqrt{a}=4\sqrt{a}\\ k,=3\sqrt{2a}-20\sqrt{2a}+10\sqrt{2a}=-7\sqrt{2a}\)