\(a,=\left(\sqrt{3}+\dfrac{2\sqrt{3}}{3}\right)\sqrt{3}=3+\dfrac{6}{3}=5\\ b,=\dfrac{3\sqrt{2}}{2}+2\sqrt{2}-\sqrt{2}+1=\dfrac{3\sqrt{2}+2\sqrt{2}+2}{2}=\dfrac{5\sqrt{2}+2}{2}\\ c,=\left(\sqrt{3}+\sqrt{2}\right)-\left(\sqrt{2}-1\right)=\sqrt{3}+1\\ d,=4\sqrt{5}-9\sqrt{5}+10\sqrt{5}=5\sqrt{5}\)