\(2,\\ a,=\dfrac{3}{13}\\ b,=\sqrt{\dfrac{25}{16}}=\dfrac{5}{4}\\ c,=\sqrt{\dfrac{2300}{23}}=\sqrt{100}=10\\ d,=\sqrt{\dfrac{12,5}{0,5}}=\sqrt{25}=5\\ 3,\\ a,=\dfrac{\sqrt{9}-\sqrt{1}}{\sqrt{2}}\cdot\sqrt{2}=3-1=2\\ b,=\left(2\sqrt{3}+3\sqrt{3}-\sqrt{3}\right)\cdot\sqrt{3}=4\sqrt{3}\cdot\sqrt{3}=12\\ c,=\left(\dfrac{2\sqrt{6}}{3}-2\sqrt{6}+\dfrac{5\sqrt{6}}{3}\right)\cdot\sqrt{6}=\dfrac{\sqrt{6}}{3}\cdot\sqrt{6}=2\\ d,=\left(2\sqrt{6}-4\sqrt{3}+5\sqrt{2}-\dfrac{\sqrt{2}}{2}\right)\cdot3\sqrt{6}\\ =36-36\sqrt{2}+30\sqrt{3}-3\sqrt{3}=36-36\sqrt{2}+27\sqrt{3}\)
\(4,\\ a,=\dfrac{7}{2\sqrt{2}}:\dfrac{5}{2\sqrt{2}}=\dfrac{7}{5}\\ b,=\sqrt{\dfrac{54x}{6x}}=\sqrt{9}=3\\ c,=\sqrt{\dfrac{1}{125}\cdot\dfrac{32}{35}\cdot\dfrac{225}{56}}=\sqrt{\dfrac{1\cdot4\cdot9}{5\cdot35\cdot7}}=\sqrt{\dfrac{36}{1225}}=\dfrac{6}{35}\)
