d: Ta có: \(\dfrac{3+2\sqrt{3}}{\sqrt{3}}+\dfrac{2+\sqrt{2}}{\sqrt{2}+1}-\left(2+\sqrt{3}\right)\)
\(=2+\sqrt{3}+\sqrt{2}-2-\sqrt{3}\)
\(=\sqrt{2}\)
e: ta có: \(\dfrac{\sqrt{10}-\sqrt{6}}{\sqrt{5}-\sqrt{3}}-\dfrac{4}{\sqrt{2}-1}+\dfrac{6}{\sqrt{2}}\)
\(=\sqrt{2}-4\sqrt{2}-4+3\sqrt{2}\)
=-4