Question

Answer 1

Ae giúp vs huhuhu

 

 

Answer 2

a) \(P=\dfrac{\sqrt{x}+1}{\sqrt{x}-2}=\dfrac{\sqrt{36}+1}{\sqrt{36}-2}=\dfrac{6+1}{6-2}=\dfrac{7}{4}\)

b) \(P=\dfrac{\sqrt{x}+1}{\sqrt{x}-2}=\dfrac{\sqrt{6-2\sqrt{5}}+1}{\sqrt{6-2\sqrt{5}}-2}=\dfrac{\sqrt{\left(\sqrt{5}-1\right)^2}+1}{\sqrt{\left(\sqrt{5}-1\right)^2}-2}=\dfrac{\sqrt{5}-1+1}{\sqrt{5}-1-2}=\dfrac{\sqrt{5}}{\sqrt{5}-3}\)

c) \(x=\dfrac{2}{2+\sqrt{3}}=\dfrac{2\left(2-\sqrt{3}\right)}{4-3}=4-2\sqrt{3}\)

\(P=\dfrac{\sqrt{4-2\sqrt{3}}+1}{\sqrt{4-2\sqrt{3}}-2}=\dfrac{\sqrt{3}-1+1}{\sqrt{3}-1-2}=\dfrac{\sqrt{3}}{\sqrt{3}-3}\)