a: Ta có: \(A=\dfrac{3}{\sqrt{3}+1}+\dfrac{2}{\sqrt{3}-1}\)
\(=\dfrac{3\sqrt{3}-3+2\sqrt{3}+2}{2}\)
\(=\dfrac{5\sqrt{3}-1}{2}\)
b: Ta có: \(B=\dfrac{\sqrt{10}-\sqrt{5}}{\sqrt{2}-1}-\dfrac{3\sqrt{5}+5}{3+\sqrt{5}}+\dfrac{2}{\sqrt{2}}\)
\(=\sqrt{5}-\sqrt{5}+\sqrt{2}\)
\(=\sqrt{2}\)